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10t^2=7t+1
We move all terms to the left:
10t^2-(7t+1)=0
We get rid of parentheses
10t^2-7t-1=0
a = 10; b = -7; c = -1;
Δ = b2-4ac
Δ = -72-4·10·(-1)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{89}}{2*10}=\frac{7-\sqrt{89}}{20} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{89}}{2*10}=\frac{7+\sqrt{89}}{20} $
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